(9y+4)^2=81y^2+72y+16

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Solution for (9y+4)^2=81y^2+72y+16 equation: 



(9y+4)^2=81y^2+72y+16

We move all terms to the left:

(9y+4)^2-(81y^2+72y+16)=0

We get rid of parentheses

-81y^2+(9y+4)^2-72y-16=0

We add all the numbers together, and all the variables

-81y^2-72y+(9y+4)^2-16=0

We move all terms containing y to the left, all other terms to the right

-81y^2-72y+(9y+4)^2=16

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